Question

A ball of mass 2.0 kg is thrown vertically upward from the top of a building. The ball’s velocity v is given as a function of time t by the equation v(t) = R - St, where R = 5 m/s and S = 10 m/s2. The positive direction is upward.

At what time does the ball reach its maximum height above the building?

A. 0.2 s

B. 0.4 s

C. 0.5 s

D. 1.0 s

E. 2.0 s

Answer 1

The ball reaches its maximum height above the building at 0.5 s.

Step-by-step explanation:

To find the time at which the ball reaches its maximum height, we need to find the time when the velocity becomes zero. The given equation for velocity as a function of time is v(t) = R - St, where R = 5 m/s and S = 10 m/s2. Setting v(t) to zero and solving for t, we get:

0 = R - St

t = R/S

Substituting the given values, we have:

t = 5 m/s / 10 m/s2 = 0.5 s

Therefore, the ball reaches its maximum height above the building at 0.5 s (C).