Question

A company installs new central-heating furnaces and has found that for 15% of all installations, a return visit is needed to make some modifications. Six installations were made in a particular week. Assume independence of outcomes for these installations.

What is the Probability that a return visit will be needed in all these cases?

Answer 1

The probability that a return visit will be needed in all six installations is 0.0000140625.

Step-by-step explanation:

To find the probability that a return visit will be needed in all six installations, we need to multiply the probabilities of each installation needing a return visit.

Since each installation is independent, the probability of each installation needing a return visit is 15% or 0.15.

Therefore, the probability that a return visit will be needed in all six cases is:

P(Return Visit in all 6 installations) = (0.15) * (0.15) * (0.15) * (0.15) * (0.15) * (0.15) = 0.0000140625