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A baseball has mass 0.145 kg . part a if the velocity of a pitched ball has a magnitude of 42.0 m/s and the batted ball's velocity is 59.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

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Final answer:

The magnitude of the change in momentum of the ball can be calculated by subtracting the initial momentum from the final momentum. The magnitude of the impulse applied to the ball by the bat is equal to the magnitude of the change in momentum.

Step-by-step explanation:

To find the magnitude of the change in momentum of the ball, we can use the equation:

change in momentum = final momentum - initial momentum

The initial momentum of the ball is given by the product of its mass and the magnitude of its initial velocity:

initial momentum = mass * initial velocity

Substituting the given values, we find:

initial momentum = 0.145 kg * 42.0 m/s

The final momentum of the ball is given by the product of its mass and the magnitude of its final velocity:

final momentum = mass * final velocity

Substituting the given values, we find:

final momentum = 0.145 kg * 59.0 m/s

Finally, we can calculate the magnitude of the change in momentum by subtracting the initial momentum from the final momentum:

change in momentum = final momentum - initial momentum

Substituting the calculated values, we get:

change in momentum = (0.145 kg * 59.0 m/s) - (0.145 kg * 42.0 m/s)

Simplifying this equation, we find the magnitude of the change in momentum of the ball.

To find the magnitude of the impulse applied to the ball by the bat, we can use the equation:

impulse = change in momentum

Substituting the calculated value for the change in momentum, we can find the magnitude of the impulse applied to the ball by the bat.

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