Question

A ball thrown vertically upward at a speed of vft/sec risés a distance d feet in t seconds, given by d=2+vt−16t² .Write an equation for the time it takes a ball thrown at a speed of 58ft/sec to rise 25 feet. NOTE: Do not solve the equation

Answer 1

The equation for the time it takes a ball thrown at a speed of 58ft/sec to rise 25 feet can be determined by substituting the given values into the equation: d = 2 + vt - 16t².

Step-by-step explanation:

The equation for the time it takes a ball thrown at a speed of 58ft/sec to rise 25 feet can be determined by substituting the given values into the equation:

d = 2 + vt - 16t²

Passing a distance of 25 feet:

25 = 2 + (58 * t) - 16 * t²

This equation represents the time it takes for the ball to reach a height of 25 feet when thrown vertically upward at a speed of 58ft/sec.