Final answer:
The molar mass of bismuth subsalicylate, with the molecular formula C7H5BiO4, is calculated by summing the products of each element's molar mass and its respective atom count in the formula, resulting in a molar mass of 362.09 g/mol. For mass conversion from milligrams to grams, divide the mass by 1000.
Step-by-step explanation:
Calculating Molar Mass of Bismuth Subsalicylate
The question requires the calculation of the molar mass of the compound bismuth subsalicylate (C7H5BiO4). To find the molar mass, we need to sum the molar masses of each constituent element in the molecular formula, each multiplied by its respective number of atoms in the formula.
- Carbon (C): 12.01 g/mol x 7 = 84.07 g/mol
- Hydrogen (H): 1.008 g/mol x 5 = 5.04 g/mol
- Bismuth (Bi): 208.98 g/mol x 1 = 208.98 g/mol
- Oxygen (O): 16.00 g/mol x 4 = 64.00 g/mol
By adding the molar masses of each element, we obtain the total molar mass of bismuth subsalicylate: 84.07 g/mol + 5.04 g/mol + 208.98 g/mol + 64.00 g/mol = 362.09 g/mol.
Note: To convert a mass from milligrams to grams, you simply divide by 1000, because there are 1000 milligrams in a gram.
Problem-Solving Strategy
When converting mass from milligrams to grams, utilize the conversion factor of 1 gram = 1000 milligrams. For determining molar mass, aggregate the product of the atomic mass of each element and its frequency in the molecule.