Final answer:
The statement is false. Setting all the weights equal to zero results in the vector 0.
Step-by-step explanation:
The statement is false. Setting all the weights equal to zero results in the vector 0.
To determine the validity of the statement, let's consider a linear combination of vectors C₁V₁ + ... + CₚVₚ, where C₁, ..., Cₚ are weights and V₁, ..., Vₚ are vectors.
If all the weights C₁, ..., Cₚ are set to zero, then the linear combination becomes 0V₁ + ... + 0Vₚ which simplifies to the zero vector, denoted as 0. The zero vector has no magnitude or direction, and all its components are zero. Therefore, the statement is false as setting all the weights equal to zero results in the vector 0.