Final answer:
The electric field at a point caused by a charged plane can be determined using Gauss's Law, with the electric field being uniform and perpendicular to the plane. Without specific methods or values for the calculation at the given point, a precise numerical answer is not achievable.
Step-by-step explanation:
The question asks to determine the electric field (E) at the point (-1, 0, 1) in the vicinity of a charged plane defined by x + 2y = 5 with a surface charge density (σ) of 6 nC/m² (nano-Coulombs per square meter). To solve this, one would typically use Gauss's Law, which relates the electric field emanating from a charged surface to the surface charge density. The electric field due to a plane of charge is uniform and perpendicular to the surface and can be calculated using E = σ/ε0, where ε0 is the vacuum permittivity. However, since the method and values necessary for calculating the specific point (-1, 0, 1) are not provided, we cannot give a specific numerical answer to this question. Generally, for a uniform plane of charge, the magnitude of E is constant at all points in space and its direction is perpendicular to the plane.