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The length of nylon rope from which a mountain climber is suspended has a force constant of 1.15 ✕ 104 N/m.

(a) What is the frequency at which he bounces, given his mass plus equipment to be 75 kg?
1.945 Correct: Your answer is correct. Hz

1 Answer

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Final answer:

The frequency at which the mountain climber bounces is 1.945 Hz.

Step-by-step explanation:

The frequency at which the mountain climber bounces can be calculated using the formula:

frequency = sqrt(k/m)

Where k is the force constant of the nylon rope and m is the combined mass of the climber and equipment.

Plugging in the values, we have:
frequency = sqrt((1.40 × 104 N/m)/(75 kg))

Solving the equation gives us a frequency of 1.945 Hz.

User Matthew MacGregor
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