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If the z-score is 1.19, the percent of the area under the normal curve between the mean and the z-score is:

a. 38.30
b. 36.43
c. 47.13
d. 36.21

1 Answer

5 votes

Final answer:

The percent of the area under the normal curve between the mean and the z-score of 1.19 is approximately 38.30%.

Step-by-step explanation:

The z-score is a measure of how many standard deviations an observation or data point is from the mean of a normal distribution. In this case, the z-score is 1.19. To find the percent of the area under the normal curve between the mean and the z-score, we can use the z-table. The z-table shows the area under the normal curve to the left of a given z-score. The z-score of 1.19 corresponds to an area to the left of approximately 0.8849. To find the percent of the area between the mean and the z-score, we subtract the area to the left of the mean (0.5) from the area to the left of the z-score. This gives us 0.8849 - 0.5 = 0.3849. To convert this to a percentage, we multiply by 100, giving us 38.49%. Therefore, the correct answer is a. 38.30%.

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