Final answer:
The length of a steel bar with a pendulum period of 1.4 s is approximately 0.98 meters, calculated using the formula L = gT^2/(4π^2), with g as gravitational acceleration.
Step-by-step explanation:
The question pertains to the calculation of the length of a pendulum based on its period. In classical physics, the period (T) of a simple pendulum is related to its length (L) by the formula T = 2π√(L/g), where g is the acceleration due to gravity (approximately 9.81 m/s2). To solve for the length when the period is given, the formula can be rearranged to L = gT2/(4π²). Given that the period of the pendulum is 1.4 s, we can calculate the length of the steel bar.
Using the formula L = gT2/(4π²), with g = 9.81 m/s2 and T = 1.4 s, the calculation would be:
L = 9.81 m/s2 × (1.4 s)2 / (4 × π2) ≈ 0.98 m
Therefore, the length of the steel bar is approximately 0.98 meters.