Question

Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addition, assume your house is the only one using electric power. At a substation the primary of a step-down transformer (turns ratio = 1:22) receives the voltage from the high-voltage transmission line. Because of your usage, a current of 51.0 mA exists in the primary of the transformer. The secondary is connected to the primary of another step-down transformer (turns ratio = 1:35) somewhere near your house, perhaps up on a telephone pole. The secondary of this transformer delivers a 240-V emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.

Answer 1

To calculate the power used by your house, use the formula P = IV. Find the current in the secondary of the second transformer using the turns ratio. Calculate the power used by your house using the secondary current and voltage.

Step-by-step explanation:

To calculate the power used by your house, we need to use the formula P = IV, where P is power, I is current, and V is voltage.

First, we need to find the current in the secondary of the second transformer. We can do this by using the turns ratio of the second transformer. The turns ratio is 1:35, which means that the secondary has 35 times more turns than the primary. Since the primary current is 51.0 mA, the secondary current is 51.0 mA / 35 = 1.46 mA.

Now we can calculate the power used by your house using the secondary current and voltage. The power is P = (1.46 mA)(240 V) = 350.4 mW.