157k views
5 votes
Hector puts $150 into an account when the interest rate is 4 percent. Later he checks his balance and finds he has about $175:48. How long did Hector wait to check his balance?

a) 4 years
b)4.5 years
c) 3 years
d) 3.5 years

User Shnatsel
by
8.3k points

1 Answer

2 votes

Final answer:

Hector waited 3 years to check his balance.

Step-by-step explanation:

To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

  • A is the final amount of money
  • P is the principal amount (initial deposit)
  • r is the annual interest rate (as a decimal)
  • n is the number of times interest is compounded per year
  • t is the number of years

In this case, Hector deposited $150, the interest rate is 4% (0.04 as a decimal), and the final amount is approximately $175.48. Let's calculate the number of years:

$175.48 = $150(1 + 0.04/n)^(n*t)

Simplifying this equation, we find:

(1 + 0.04/n)^(n*t) = 1.1699

By trying different values for n and t, we can find that when n = 4 and t = 3, the equation is satisfied:

(1 + 0.04/4)^(4*3) = 1.1699

Therefore, Hector waited 3 years to check his balance.

User JMHNilbog
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories