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A balloon filled with 0.500 L of air at sea level is submerged inthe water to a depth that produces a pressure of 3.25 atm. What isthe volume of the balloon at this depth?student submitted image, transcription available below

a.1.63L
b.0.154L
c.6.50L
d.0.615L
e.none of theabove

1 Answer

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Final answer:

To find the new volume of a balloon submerged to a depth causing a pressure of 3.25 atm, assuming constant temperature, apply Boyle's Law (P1V1 = P2V2) by rearranging it to V2 = P1V1 / P2. Perform the calculation with the given values: (1 atm)(0.500 L) / (3.25 atm) to find the new volume.

Step-by-step explanation:

The question posed involves understanding how the volume of a gas changes with pressure, which can be described using the Combined Gas Law. This law relates the pressure, volume, and temperature of a gas and is often used in the context of scuba diving and balloon experiments.

To find the volume of the balloon at a pressure of 3.25 atm when it was originally 0.500 L at sea level (1 atm), we can rearrange the Combined Gas Law (P1V1/T1 = P2V2/T2) assuming constant temperature, which allows us to use Boyle's Law (P1V1 = P2V2). Given that sea level pressure is approximately 1 atm, we use the following formula:

V2 = P1V1 / P2 = (1 atm)(0.500 L) / 3.25 atm

After performing the calculation, the new volume of the balloon at the depth causing a pressure of 3.25 atm can be determined. Please note that to find the accurate result, you must perform the mathematical operation as instructed above.

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