Question

Given that 4 NH₃ + 5 O₂--->4NO+6H₂O, when 4.50 mol of H₂O are formed.

a. The mole of NO formed is:
b. The # of NO molecules formed is:

Answer 1

The number of moles of NO formed is 1.33 mol and the number of NO molecules formed is approximately 7.99 x 10^23 molecules.

Step-by-step explanation:

The balanced chemical equation for the reaction is:

4 NH₃ + 5 O₂ ➞ 4 NO + 6 H₂O

From the equation, we can determine the mole ratio of H₂O to NO is 6:4 or 3:2. Therefore, for every 3 moles of H₂O formed, 2 moles of NO are formed.

To find the number of moles of NO formed, we can set up a proportion:

x mol NO / 3 mol H₂O = 2 mol NO / 4.50 mol H₂O

Solving for x, we get x = (3 mol H₂O * 2 mol NO) / 4.50 mol H₂O = 1.33 mol NO

Therefore, the number of moles of NO formed is 1.33 mol.

Since 1 mole contains Avogadro's number (6.02 × 10^23) of molecules, we can find the number of NO molecules formed by multiplying the number of moles by Avogadro's number:

1.33 mol NO * 6.02 × 10^23 molecules/mol = 7.99 × 10^23 molecules

Therefore, the number of NO molecules formed is approximately 7.99 × 10^23 molecules.