Final answer:
To calculate the theoretical yield of 1-bromobutane in the experiment, use the stoichiometry of the balanced chemical equation. The limiting reagent in this case is 1-butanol.
Step-by-step explanation:
The limiting reagent in the production of 1-bromobutane is 1-butanol. To calculate the theoretical yield of 1-bromobutane in your experiment, you need to use the stoichiometry of the balanced chemical equation. Let's assume the balanced equation is:
1-butanol + HBr → 1-bromobutane + H2O
From the equation, we can see that the mole ratio between 1-butanol and 1-bromobutane is 1:1. This means that 1 mole of 1-butanol will produce 1 mole of 1-bromobutane.
If you have the initial moles of 1-butanol, you can calculate the theoretical yield of 1-bromobutane by multiplying the moles of 1-butanol by the molar mass of 1-bromobutane. For example, if you have 0.5 moles of 1-butanol, and the molar mass of 1-bromobutane is 150 g/mol, the theoretical yield would be 0.5 moles * 150 g/mol = 75 grams.