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A car of mass 1.5 t (1t=10³kg) traveling at 50km /h must be brought to a stop. How much Kinetic Energy must be dissipated?

User Taniesha
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1 Answer

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Final answer:

The kinetic energy of the car must be dissipated to bring it to a stop. The amount of kinetic energy can be calculated using the formula KE = 1/2 * m * v^2, where m is the mass of the car and v is its velocity. After converting the mass and velocity to the appropriate units, we can substitute the values into the formula to find the answer.

Step-by-step explanation:

The kinetic energy of a moving object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity. In this question, the car has a mass of 1.5 t (1t=10^3kg) and is traveling at 50 km/h. To calculate the kinetic energy, we need to convert the mass to kg and the velocity to m/s:

Mass of the car = 1.5 t = 1.5 * 10^3 kg

Velocity of the car = 50 km/h = (50 * 1000) / 3600 = 13.89 m/s

Now we can substitute the values into the formula:

KE = 1/2 * 1.5 * 10^3 * (13.89)^2 = 905625 J

Therefore, the amount of kinetic energy that must be dissipated to bring the car to a stop is 905,625 Joules.

User Ryan Li
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