Final answer:
The question pertains to calculating the percentage of manganese in an ore sample given the mass of a presumably manganese oxide. Accurate calculation requires the correct manganese oxide formula to use stoichiometry for finding the mass and hence the percentage of manganese.
Step-by-step explanation:
The student is asking to calculate the percentage of manganese (Mn) in a manganese ore based on the mass of manganese oxide (presumably MnO2, although the formula given has a typo as 'Mn,O') obtained from a 152-gram sample of the ore. To solve this, one would need to use stoichiometry to convert from the mass of manganese oxide obtained back to the mass of manganese. Since the mass of manganese is not directly provided, the percentage of manganese in the ore cannot be calculated precisely without the correct formula of the manganese oxide. Typically, the molar mass of the oxide is used in the calculation, along with the molar mass of elemental manganese. If we assume the oxide is MnO2, the calculation would follow these basic steps:
Determine the moles of manganese oxide by dividing the mass of manganese oxide by its molar mass.
Use the stoichiometry of the oxide (which indicates that each mole of MnO2 contains one mole of Mn) to find the moles of manganese in the sample.
Convert the moles of manganese to grams using its molar mass.
Finally, calculate the percentage by weight of manganese (%w/w) in the ore by dividing the mass of manganese obtained by the initial mass of the ore sample, and then multiplying by 100.