Question

A flea jumps straight up to a maximum height of 0.360 m. What is its initial velocity as it leaves the ground?Take the magnitude of free-fall acceleration to be 9.80 m/s^2. Ignore air resistance.

Answer 1

The initial velocity of the flea as it leaves the ground is approximately 2.84 m/s.

Step-by-step explanation:

To calculate the initial velocity as the flea leaves the ground, we need to use the kinematic equation for vertical motion:

vf^2 = vi^2 + 2ad

Where:

• vf is the final velocity (which is 0 m/s at the maximum height)
• vi is the initial velocity
• a is the acceleration (which is -9.80 m/s^2 due to gravity)
• d is the displacement (which is the maximum height, 0.360 m)

Plugging in the given values:

0 = vi^2 + 2(-9.80)(0.360)

Solving for vi:

vi = sqrt(2(9.80)(0.360))

vi ≈ 2.84 m/s

Therefore, the initial velocity of the flea as it leaves the ground is approximately 2.84 m/s.