Question

a 70 kg driver gets into an empty taptap to start the day's work. the springs compress 2.2×10−² m . what is the effective spring constant of the spring system in the taptap?

Answer 1

The effective spring constant of the spring system in the taptap is approximately 317,273 N/m.

Step-by-step explanation:

To find the effective spring constant of the spring system in the taptap, we can use Hooke's law formula which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Formula: F = -kx

Given: Driver's mass (m) = 70 kg, Spring displacement (x) = 2.2×10-2 m

Using Hooke's law, we can rearrange the formula to solve for the spring constant (k):

k = -F/x

Using the driver's weight as the force (F = m×g), we can calculate the spring constant:

k = -(m×g)/x

Substituting the values, we get:

k = -(70 kg×9.8 m/s²)/(2.2×10-2 m)

Simplifying the expression, we find that the effective spring constant of the spring system in the taptap is approximately 317,273 N/m.