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a signal goes through two amplification stages. the first stage has a gain of a1=73 v/v, and the second has a gain of a2=28 v/v. find the total gain and express it in db.

User Motsi
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Final answer:

The total gain of two amplification stages with gains of 73 V/V and 28 V/V is multiplied to get 2044 V/V. This total gain, when converted to decibels (dB), is approximately 66.21 dB.

Step-by-step explanation:

To find the total gain of a signal that goes through two amplification stages, you multiply the gains of the individual stages when the gains are in voltage/voltage (V/V) units. So, the total gain at is:

at = a1 × a2

at = 73 V/V × 28 V/V

at = 2044 V/V

Next, to express this total gain in decibels (dB), use the formula:

GdB = 20 × log10(at)

GdB = 20 × log10(2044)

GdB = 20 × 3.3104

GdB ≈ 66.21 dB

Therefore, the total gain in dB of the two amplification stages is approximately 66.21 dB.

User Atomaras
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