Final answer:
The energy of an electron with n=6 in a hydrogen atom using the Bohr model is approximately -0.3778 eV.
Step-by-step explanation:
The energy of an electron in a hydrogen atom with n=6 can be determined using the Bohr model. The energy of an electron in the nth orbit of a hydrogen atom is given by the formula:
E = -13.6 eV / (n^2)
where E is the energy and n is the principal quantum number. Plugging in n=6 into the formula, we get:
E = -13.6 eV / (6^2) = -0.3778 eV
Therefore, the energy of an electron with n=6 in a hydrogen atom is approximately -0.3778 eV.