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How many moles of the excess reactant remain after the completion of the reaction?

Sodium hydroxide reacts with carbon dioxide as follows: 2NaOH(s) + CO₂(g) yields Na₂CO₃(s) + H₂O(l)

User Al Kepp
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Final answer:

To determine the moles of excess NaOH remaining after the reaction with CO₂, use the stoichiometry of the balanced chemical equation, subtracting twice the moles of reacted CO₂ from the initial moles of NaOH.

Step-by-step explanation:

To find out how many moles of the excess reactant remain after the completion of the reaction, where sodium hydroxide reacts with carbon dioxide, we start with the balanced chemical equation: 2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l). This equation tells us that 2 moles of NaOH react with 1 mole of CO₂ to produce 1 mole of Na₂CO₃ and 1 mole of H₂O.

Suppose we have more NaOH than needed to completely react with CO₂. After the reaction is complete, assuming CO₂ is the limiting reactant, we can calculate the remaining amount of NaOH using stoichiometry. If the initial moles of NaOH and CO₂ are known, we subtract the consumed moles of NaOH (twice the moles of CO₂ reacted) from the initial moles to find the moles of excess NaOH.

User Pedro Manfredi
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