Question

The molar heat capacity of graphite is (units: J K-1 mol-1 with T in K): Cp.m=16.88+4.77×10^-3T−8.54×10^5/T^2 Calculate ΔS (in J K-1) when 1.00 mol of graphite is heated from 300 K to 1800 K at fixed pressure.

Answer 1

To calculate ΔS when 1.00 mol of graphite is heated from 300 K to 1800 K at fixed pressure, you can use the formula ΔS = ∫(Cp.m/T)dT

Step-by-step explanation:

To calculate ΔS (in J K-1) when 1.00 mol of graphite is heated from 300 K to 1800 K at fixed pressure, we can use the formula:

ΔS = ∫(Cp.m/T)dT

where Cp.m is the molar heat capacity of graphite in J K-1 mol-1. Plugging in the given values:

ΔS = ∫(16.88+4.77×10^-3T−8.54×10^5/T^2)dT from 300 to 1800 K

Integrating this expression will give us the value of ΔS in J K-1.