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The average rent in a city is $1,220 per month with a standard deviation of $250. Assume rent follows the normal distribution. [You may find it useful to reference the z table.] a. What percentage of rents are between $470 and $1,970? (Round your answer to 2 decimal places.) Percentage of rents % b. What percentage of rents are less than $470? (Round your answer to 2 decimal places.) Percentage of rents % Prey 11 of 15 Neyt b. What percentage of rents are less than $470? (Round your answer to 2 decimal places.) Percentage of rents % c. What percentage of rents are greater than $1,470? (Round your answer to 2 decimal places.) Percentage of rents %

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Final answer:

Using the normal distribution and z-scores, we find that 99.74% of rents are between $470 and $1,970, 0.13% are less than $470, and 15.87% are greater than $1,470.

Step-by-step explanation:

To answer the question about the percentage of rents within certain ranges, we need to use z-scores and the normal distribution table. Z-scores are calculated by subtracting the mean from the observation and then dividing by the standard deviation. In this case, the mean is $1,220 and the standard deviation is $250.

Calculating Z-Scores

For $470:
z = (470 - 1220) / 250 = -3
For $1,970:
z = (1970 - 1220) / 250 = 3

Using the z-table, we find that the area to the left of z = 3 is nearly 0.9987, and the area to the left of z = -3 is nearly 0.0013.

To find the percentage of rents between $470 and $1,970, we subtract the smaller area from the larger area:
0.9987 - 0.0013 = 0.9974

Multiplying by 100, we get 99.74% of rents fall between $470 and $1,970.

Percentage of Rents Less Than $470

The area to the left of z = -3 is 0.0013, or 0.13%.

Percentage of Rents Greater Than $1,470

For $1,470:
z = (1470 - 1220) / 250 = 1
Using the z-table, the area to the left of z = 1 is approximately 0.8413.

Since we want the area greater than $1,470, we subtract this from 1:
1 - 0.8413 = 0.1587

Multiplying by 100, we get 15.87% of rents are greater than $1,470.

User Bruce Adams
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