Final answer:
To find the initial horizontal component of the velocity of the ball thrown horizontally from a tall building, we can use the formulas for horizontal distance and time of flight. By substituting the given values into the formulas and solving, we find that the initial horizontal component of the velocity is approximately 16.8 m/s.
Step-by-step explanation:
To find the initial horizontal component of the velocity, we can use the formula:
vx = d/t
where vx is the initial horizontal component of the velocity, d is the horizontal distance the ball travels, and t is the time the ball is in the air.
In this case, d = 50.0 m and t can be found using the formula:
t = √(2h/g)
where h is the height of the building and g is the acceleration due to gravity. In this case, h = 350.0 m and g ≈ 9.8 m/s2.
Once we have t, we can substitute it back into the first formula to find vx.
By evaluating the expressions, we find that the initial horizontal component of the velocity is approximately 16.8 m/s.