Question

A car moves from the point (3.0m)x + (5.0m)y to the point (8.0 m)x -(7.0 m)y in 2.0 s. What is themagnitude of the average velocity of the car.?

Answer 1

The magnitude of the average velocity of the car is 6.5m/s.

Step-by-step explanation:

The average velocity of a car can be determined by calculating the displacement of the car divided by the time taken. In this case, the car moves from the point (3.0m, 5.0m) to the point (8.0m, -7.0m) in 2.0 seconds. To find the displacement, we subtract the initial position (3.0m, 5.0m) from the final position (8.0m, -7.0m) to get a displacement of (5.0m, -12.0m). The magnitude of the displacement is calculated using the Pythagorean theorem, which gives us √((5.0m)^2 + (-12.0m)^2) = √(25.0m^2 + 144.0m^2) = √(169.0m^2) = 13.0m.

Next, we divide the magnitude of displacement by the time taken to get the average velocity: 13.0m / 2.0s = 6.5m/s.