Question

according to the following balanced reaction, how many moles of hno3 are formed from 3.75 moles of no2 if there is plenty of water present? 3 no2(g) h2o(l) → 2 hno3(aq) no(g)

Answer 1

To determine the moles of HNO3 produced from 3.75 moles of NO2, we apply the stoichiometric ratio from the balanced reaction, resulting in 2.50 moles of HNO3.

Step-by-step explanation:

The question asks how many moles of HNO3 are formed from 3.75 moles of NO2 according to the balanced chemical reaction 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g). To solve this, we use the stoichiometric ratio from the balanced equation which shows that 3 moles of NO2 produce 2 moles of HNO3.

Using a simple cross-multiplication, we find that:

• 3 moles NO2 → 2 moles HNO3
• 3.75 moles NO2 → X moles HNO3

To find the value of X, we calculate (3.75 moles NO2) × (2 moles HNO3) / (3 moles NO2). This gives us 2.50 moles of HNO3.

To find how many moles of HNO3 are formed from 3.75 moles of NO2, we need to use the stoichiometry of the balanced chemical equation. From the equation, we can see that for every 3 moles of NO2, 2 moles of HNO3 are formed.

So, we set up a proportion:

3 moles NO2/2 moles HNO3 = 3.75 moles NO2/x moles HNO3

Solving for x, we get:

x = (3.75 moles NO2)(2 moles HNO3)/(3 moles NO2)

x = 2.5 moles HNO3