Question

I'm giving 100 points if you answer these questions. CORRECTLY
-3x+5>20
1/2x-12<6

Answer 1

x< -5, x<36

Explanation:

`-3x+5>20} \atop {(1)/(2)x-12<6 }} \right. \\`

Start with the first equation and solve for x

-3x+5>20

-5 -5

-3x>15

/-3 /-3

x< -5

Do the second:

`(1)/(2)x-12<6`

+12 +12

`(1)/(2)x`<18

/0.5 /0.5

x< 36

Answer 2

Are they a system or separate inequalities? I'm not sure but either way I will solve each:

`\begin{bmatrix}-3x+5>20\\ (1)/(2)x-12<6\end{bmatrix}`

`-3x+5>20,\\-3x>15,\\x<-5`

`(1)/(2)x-12<6,\\(1)/(2)x<18,\\x<36`

Now if it were a system, the solution would be x<-5, since x<36 is the restriction. Otherwise just take x<-5 and x<36 independent of each other.