Question

Suppose you throw a ball straight up from the ground with a velocity of 224 feet per second. as the ball moves up, gravity slows it. eventually, the ball begins to fall back to the ground. the height h of thr ball after t seconds in the air is given by the equation h=-16t² + 224t. use the given information to answer.

find the height of the ball after four seconds.

Answer 1

The height of the ball after four seconds is 640 feet.

Step-by-step explanation:

The equation given to calculate the height of the ball after t seconds is h = -16t² + 224t. To find the height of the ball after four seconds, we can substitute t = 4 into the equation:

h = -16(4)² + 224(4)

h = -16(16) + 224(4)

h = -256 + 896

h = 640

Therefore, the height of the ball after four seconds is 640 feet.