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Miranda graphed (y + 1)2 > 6(x - 2).

Which could Miranda use to justify that her graph is correct? Check all that apply.
Because only the y quantity is squared, the curve is a parabola.
The parabola opens right because 6 is in front of the x-quantity.
There is a strict inequality so the boundary is included in the solution set.
The shading is outside the parabola because (0,0) satisfies the inequality.
The values subtracted from x and y in the equation are the coordinates of the vertex which
O O O O

User CKT
by
6.6k points

2 Answers

11 votes

Answer:

A, B, D, and E

Explanation:

right on edge 2022 :)

User Jive Boogie
by
7.6k points
6 votes

Answer:

The correct options that describe the inequality (y + 1)² > 6·(x - 2)

1) Because only the 'y' quantity is squared the curve is a parabola

2) The parabola opens right because 6 is in front of the 'x' quantity

3) The shading area is outside the parabola because (0, 0) satisfies the inequality

4) The values subtracted from 'x', and 'y' in the equation are the coordinates of the vertex

Explanation:

The given inequality graphed by Miranda is presented as follows;

(y + 1)² > 6·(x - 2)

By simplification, we get;

Given that the inequality is of the form (y - k)² > 4·p·(x - h), we have;

The curve is a parabola as only the 'y' quantity is squared

-k = 1

∴ k = -1

4·p = 6

∴ p = 6/4 = 3/2 = 1.5

p = 1.5

-h = -2

∴ h = 2

The vertex of the parabola = (h, k) = (2, -1)

The axis of symmetry = The x-axis

p = 1.5 > 0, therefore, the parabola opens right

Therefore, the parabola opens right because 6 is in front of the 'x' quantity

There is a strict inequality therefore the boundary is not included in the solution set

When x = 0 and y = 0, we have;

(y + 1)² > 6·(x - 2)

(0 + 1)² > 6·(0 - 2)

1² > 6 × (-2)

1 > -12, which satisfies the inequality and (0, 0) is on the left and below the vertex, therefore, the shaded area is outside the parabola

The vertex of the parabola given in the form, (y - k)² > 4·p·(x - h), is (h, k), which are the values subtracted from 'x', and 'y' in the equation

Therefore, the vertex of the given parabola, (y + 1)² > 6·(x - 2) = (2, -1)

User HMR
by
6.4k points
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