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If 3.0 l of a 5.2 m SrCl₂ solution is diluted to 50 l , what is the molarity of the diluted solution?

User Psirus
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1 Answer

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Final answer:

To calculate the molarity of the diluted solution, use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. In this case, the molarity of the diluted solution is 0.312 M.

Step-by-step explanation:

To calculate the molarity of the diluted solution, we can use the formula:

M1V1 = M2V2

Where:

  • M1 is the initial molarity
  • V1 is the initial volume
  • M2 is the final molarity
  • V2 is the final volume

In this case, the initial molarity (M1) is 5.2 M, the initial volume (V1) is 3.0 L, and the final volume (V2) is 50 L. We need to find the final molarity (M2).

Using the formula and plugging in the values, we have:

(5.2 M) * (3.0 L) = (M2) * (50 L)

Cross multiplying and solving for M2, we get:

M2 = (5.2 M * 3.0 L) / 50 L

M2 = 0.312 M

Therefore, the molarity of the diluted solution is 0.312 M.

User Yulric Sequeira
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