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If the same amount (5.26g) of zinc is melted it takes 579 joules to completely melt the sample what is the heat of fusion of zinc

User Rinchik
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Final answer:

The heat of fusion of zinc is calculated by dividing the total energy required to melt the sample by the mass of the zinc. For a 5.26g sample of zinc that requires 579 joules to melt, the heat of fusion is 110.08 J/g.

Step-by-step explanation:

The student is asking about the heat of fusion of zinc, which is the amount of heat required to change zinc from a solid to a liquid at its melting point without changing its temperature. Given that 5.26 grams of zinc require 579 joules to melt completely, to find the heat of fusion per gram, you would divide the total energy by the mass of zinc:

Heat of fusion (J/g) = Total energy required (J) / Mass of zinc (g)

The calculation for the heat of fusion per gram is therefore:

579 J / 5.26 g = 110.08 J/g

The heat of fusion of zinc is 110.08 joules per gram (J/g).

User Giorgos Altanis
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