Question

If 12.0 L of NO₂( g), measured at STP. is allowed to react with 15.5 g of water, find the limiting reagent.

a. NO₂( g)
b. H₂O(l)

Answer 1

To determine the limiting reagent in this reaction, compare the number of moles of NO₂ and H₂O. The limiting reagent is NO₂(g).

Step-by-step explanation:

To determine the limiting reagent in this reaction, we need to compare the number of moles of NO₂ and H₂O.

First, calculate the number of moles of NO₂ using the ideal gas law:

moles of NO₂ = volume (L) x (1 mole/22.4 L)

moles of NO₂ = 12.0 L x (1 mole/22.4 L) = 0.536 moles

Next, calculate the number of moles of H₂O using the molar mass:

moles of H₂O = mass (g) / molar mass

moles of H₂O = 15.5 g / 18.015 g/mol ≈ 0.861 moles

Since the number of moles of NO₂ is less than the number of moles of H₂O, the limiting reagent is NO₂(g).