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a particle of mass 200gm executes SHM.the restoring force is provided by a spring of force constant 80N/m.the time period of oscillation is?​

User Fetzig
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1 Answer

10 votes

Answer:

time period of oscillation is 0.31 seconds

Step-by-step explanation:

we shall know the formula:


T = 2\pi \sqrt{(m)/(k) } ......where m is mass and k is force constant.

change 200gm into kg, then it will be 0.2 kg

T = 2π√0.2÷80

T = 0.314 seconds

T = 0.31 seconds rounded to 2 decimal places.

User Maglob
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