214k views
4 votes
Doubling the concentration of one reactant increases the rate of a reaction two times. What is the order of the reaction with respect to that reactant?

a. zero
b. first
c. second
d. third

User Earnest
by
8.0k points

1 Answer

5 votes

Final answer:

The order of a reaction to doubling the concentration of a reactant, which results in a two-fold increase in rate, is first order with respect to that reactant.

Step-by-step explanation:

The order of a reaction with respect to a particular reactant is determined by how the concentration of that reactant affects the rate of the reaction. In this case, if doubling the concentration of one reactant leads to a doubling of the reaction rate, the reaction is considered first-order with respect to that specific reactant.

In a first-order reaction, the rate of the reaction is directly proportional to the concentration of the reactant raised to the power of 1. Therefore, if [A] represents the concentration of the reactant, the rate equation for a first-order reaction would be: Rate=[]Rate=k[A]where k is the rate constant.

So, in summary, if doubling the concentration of a reactant results in a twofold increase in the reaction rate, the reaction is first-order with respect to that reactant.

User Boris Savic
by
8.7k points