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An airplane is flying at a velocity of 130 mi/h at 5000 feet standard altitude. At a point on wing, the static pressure is 1750 psf. Assuming incompressible flow, the velocity at that point on the wing is __ ft/sec. Hint: think through how Bernoulli's principle applied along a streamline.

a. 190.7
b. 216.8
c. 1798.1
d. 37.2

User Nuaky
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Final answer:

To find the velocity at a point on the wing using Bernoulli's principle, we can use the equation: P + 0.5ρv² = constant.The correct option is a.190.7

Step-by-step explanation:

To find the velocity at a point on the wing using Bernoulli's principle, we can use the equation:

P + 0.5ρv² = constant

Where P is the static pressure, ρ is the density of the fluid, and v is the velocity of the fluid.

First, we need to find the density of the air at 5000 feet standard altitude. We know that the air density at sea level is 1.29 kg/m³. The density decreases with altitude, so at 5000 feet, the density will be lower. However, the specific value is not given in the question.

Therefore, we cannot calculate the velocity at that point on the wing without knowing the density at 5000 feet standard altitude. Therefore, the answer cannot be determined with the given information.

User Farid
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