Final answer:
This question asks to draw the Lewis structures and describe the molecular geometry of three organic compounds.
Step-by-step explanation:
For each of the given compounds:
a) ch3coch2chchcooh
- The Lewis structure of the compound is as follows:
H3C - C(=O) - CH2 - C(CH3) - CH2 - COOH
- The bond angles around each carbon atom are approximately 109.5 degrees, indicating a tetrahedral geometry.
- Each carbon atom in the compound exhibits sp3 hybridization.
b) ch3ch2c(ch3 )2ch2cooch3
- The Lewis structure of the compound is as follows:
H3C - CH2 - C(CH3)2 - CH2 - COOCH3
- The bond angles around each carbon atom are approximately 109.5 degrees, indicating a tetrahedral geometry.
- Each carbon atom in the compound exhibits sp3 hybridization.
c) ncch2coch2cho
- The Lewis structure of the compound is as follows:
N≡C - CH2 - C(=O) - CHO
- The bond angles around the carbon atoms vary depending on the number and type of atoms bonded to them.
- The carbon atom bonded to the nitrogen atom exhibits sp hybridization, while the other carbon atom exhibits sp2 hybridization.