Final answer:
The unit vector in the direction of 6, -4 is (6/2sqrt(13))î + (-4/2sqrt(13))ĵ.
Step-by-step explanation:
To find the unit vector in the direction of 6, -4, we need to divide the vector by its magnitude. The magnitude of vector a = 6î - 4ĵ is given by |a| = sqrt((6)^2 + (-4)^2) = sqrt(36 + 16) = sqrt(52) = 2sqrt(13). Dividing the vector a = 6î - 4ĵ by its magnitude, we get the unit vector in the direction of 6, -4 as (6/2sqrt(13))î + (-4/2sqrt(13))ĵ.