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How many atoms of titanium are there in 0.650 mole of each of the following?

a. ilmenite, FeTiO,
b. titanium(IV) chloride
c. Ti₂O₃ atoms
d. Ti₃O₅

User Musicmatze
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Final answer:

The number of titanium atoms in 0.650 mole of various compounds is calculated using Avogadro's number. For a compound with one titanium atom per formula unit, the count is 3.91 \u00d7 1023, and it increases proportionally with the number of titanium atoms per formula unit.

Step-by-step explanation:

To calculate the number of titanium atoms in 0.650 mole of various compounds, we use Avogadro's number, which is 6.022 \u00d7 1023 atoms/mole. This number represents how many atoms are in one mole of any given substance:

  • For ilmenite (FeTiO3), which has one titanium atom per formula unit, the calculation is straightforward: 0.650 moles \u00d7 6.022 \u00d7 1023 atoms/mole = 3.91 \u00d7 1023 titanium atoms.
  • For titanium(IV) chloride (TiCl4), again there is one titanium atom per formula unit, resulting in the same number of titanium atoms as in ilmenite.
  • For Ti2O3, there are two titanium atoms per formula unit, so the number of titanium atoms is doubled: 0.650 moles \u00d7 2 \u00d7 6.022 \u00d7 1023 atoms/mole = 7.82 \u00d7 1023 titanium atoms.
  • For Ti3O5, there are three titanium atoms per formula unit, hence: 0.650 moles \u00d7 3 \u00d7 6.022 \u00d7 1023 atoms/mole = 1.17 \u00d7 1024 titanium atoms.
User Mitchell Skurnik
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