Question

A jet makes a landing traveling due east iwht a speed of 115 m/s. If the jet comes to rest in 13.0s, what are the magnitude and direction of its average acceleration.

Answer 1

The magnitude of the average acceleration is 8.846 m/s^2 and the direction is west.

Step-by-step explanation:

The average acceleration of the jet can be found using the formula:

average acceleration = (final velocity - initial velocity) ÷ time

The final velocity of the jet is 0 m/s, the initial velocity is 115 m/s, and the time is 13.0 s.

Plugging in these values, we get:

average acceleration = (0 m/s - 115 m/s) ÷ 13.0 s

average acceleration = -115 m/s ÷ 13.0 s

average acceleration = -8.846 m/s2

Therefore, the magnitude of the average acceleration is 8.846 m/s2 and the direction is west (opposite to the direction of motion).

Answer 2

The magnitude and direction of the average acceleration of the jet can be determined using the equation: average acceleration = (final velocity - initial velocity) / time. The magnitude of the average acceleration of the jet is 8.85 m/s² and its direction is west.

Step-by-step explanation:

The magnitude and direction of the average acceleration of the jet can be determined using the equation:

average acceleration = (final velocity - initial velocity) / time

Given that the final velocity is 0 m/s (because the jet comes to rest) and the initial velocity is 115 m/s (because the jet is traveling due east with a speed of 115 m/s), and the time is 13.0 s, we can substitute these values into the equation:

average acceleration = (0 m/s - 115 m/s) / 13.0 s

average acceleration = -8.85 m/s²

Therefore, the magnitude of the average acceleration of the jet is 8.85 m/s² and its direction is west.