Question

There are 52.3 g of sucrose (C₁₂H₂₂0₁₁) is a 0.750 L bottle of soda. What is the concentration of sucrose in the 0.750 L of this solution? Select the correct answer below:

a)0.152 M
b)0.203 M
c)0.750 M
d)4.93 M

Answer 1

After calculating the moles of sucrose using its molar mass, divide by the volume of the solution to find the molarity. In this case, 52.3 g of sucrose in a 0.750 L bottle of soda gives a concentration of 0.203 M.

Step-by-step explanation:

To calculate the concentration of sucrose in a 0.750 L bottle of soda, we first need to establish how many moles of sucrose are in the given mass. The molar mass of sucrose (C₁₂H₂₂O₁₁) is approximately 342.3 g/mol. Therefore, the number of moles of sucrose in the 52.3 g sample is:

number of moles = mass (g) / molar mass (g/mol) = 52.3 g / 342.3 g/mol = 0.1528 mol (rounded to four significant figures)

Next, we divide the moles of sucrose by the volume of the solution in liters to get the molarity of the solution:

molarity (M) = moles of solute / volume of solution in liters = 0.1528 mol / 0.750 L = 0.203 M (rounded to three significant figures)

Therefore, the concentration of sucrose in the 0.750 L of soda is 0.203 M.