Final answer:
Any two real numbers, a and b, have a real number c as a solution to the equation at² + bt + c = 0, where a, b, and c are constants.
Step-by-step explanation:
Given any two real numbers a and b, there is a real number c such that c is the solution to the equation at² + bt + c = 0, where the constants are a, b, and c.
For example, if a = 1.00, b = 10.0, and c = -200, we can substitute these values into the quadratic formula to find the solutions for c. Using the formula:
c = (-b ± √(b² - 4ac))/(2a)
we get:
c = (-10 ± √(10² - 4(1)(-200)))/(2(1))
which simplifies to:
c = -20 or c = -180.