Final answer:
The set of all vectors in R² with the second component as the cube of the first follows the form (x, x³). Their magnitude can be calculated using the Pythagorean theorem as R = √(x² + x¶).
Step-by-step explanation:
The set of all vectors in R² whose second component is the cube of the first can be described as all vectors of the form ℓ = (x, y) where y = x³.
To resolve this vector into components along the x and y axes, one would consider x to be the x-component and x³ to be the y-component. Since these components share a common axis, adding them follows the rule of ordinary number addition along their respective directions.
The magnitude R of any of these vectors can be found using the Pythagorean theorem as R = √(x² + y²) = √(x² + (x³)²), which simplifies to R = √(x² + x¶).