Final answer:
The displacement and velocity of a ball thrown straight up can be calculated using the equations of motion. The displacement equation is y = y0 + v0y*t + (1/2)*ay*t^2 and the velocity equation is vy = v0y + ay*t. By plugging in the given values for time and initial velocity, we can find the displacement and velocity at each given time.
Step-by-step explanation:
To calculate the displacement and velocity of a ball thrown straight up, we can use the equations of motion. The equation for displacement is given by:
Displacement (y) = y0 + v0y*t + (1/2)*ay*t^2
where y0 is the initial position (0 in this case), v0y is the initial vertical velocity, t is the time, and ay is the acceleration due to gravity (-9.8 m/s^2).
The equation for velocity is given by:
Velocity (vy) = v0y + ay*t
where vy is the vertical velocity.
Calculations:
(a) At t = 0.500 s:
Displacement = 0 + (15.0 m/s)*(0.5 s) + (1/2)*(-9.8 m/s^2)*(0.5 s)^2
Velocity = (15.0 m/s) + (-9.8 m/s^2)*(0.5 s)
(b) At t = 1.00 s:
Displacement = 0 + (15.0 m/s)*(1.0 s) + (1/2)*(-9.8 m/s^2)*(1.0 s)^2
Velocity = (15.0 m/s) + (-9.8 m/s^2)*(1.0 s)
(c) At t = 1.50 s:
Displacement = 0 + (15.0 m/s)*(1.5 s) + (1/2)*(-9.8 m/s^2)*(1.5 s)^2
Velocity = (15.0 m/s) + (-9.8 m/s^2)*(1.5 s)
(d) At t = 2.00 s:
Displacement = 0 + (15.0 m/s)*(2.0 s) + (1/2)*(-9.8 m/s^2)*(2.0 s)^2
Velocity = (15.0 m/s) + (-9.8 m/s^2)*(2.0 s)