Final answer:
To find a nontrivial solution to the quadratic equation x² + 0.0211x - 0.0211 = 0, the quadratic formula should be used with coefficients a=1, b=0.0211, and c=-0.0211.
Step-by-step explanation:
The question appears to be asking for a solution to the quadratic equation x² + 0.0211x - 0.0211 = 0. To solve for x, we can apply the quadratic formula which is x = (-b ± √(b² - 4ac)) / (2a), where a, b, and c are coefficients from the equation ax² + bx + c = 0 respectively. In this case, a = 1, b = 0.0211, and c = -0.0211. Plugging these values into the quadratic formula, we would find the possible values for x that satisfy the equation. Without solving it completely, we can see by inspection that one nontrivial solution (meaning not just x=0) could be when the positive and negative terms involving x cancel each other out.