Final answer:
The average net force required to bring the car to rest is 21,210 N in the opposite direction of motion.
Step-by-step explanation:
To calculate the average net force required to bring the car to rest, we need to use the equation F = m*a, where F is the force, m is the mass of the car, and a is the acceleration. In this case, the car is brought to rest, so the final velocity is 0 m/s. The initial velocity is 27.8 m/s and the distance is 55 m.
Using the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance, we can solve for the acceleration. Rearranging the equation, we have a = (v² - u²) / (2*s).
Substituting the given values, we have a = (0² - 27.8²) / (2*55) = -14.14 m/s² (negative because the car is decelerating). Now, we can calculate the force using F = m*a, where m is the mass of the car. Substituting the values, we have F = 1500 kg * (-14.14 m/s²) = -21,210 N. Since force is a vector quantity, the average net force required to bring the car to rest is 21,210 N in the opposite direction of motion.