Final answer:
Iron(II) bromide, with the formula FeBr2, is soluble in water because it dissociates into iron cations and bromide anions.
Step-by-step explanation:
Iron(II) bromide is indeed soluble in water. While elemental bromine itself is only slightly soluble in water, its compounds, such as iron(II) bromide, are generally soluble. The formula for iron(II) bromide is FeBr2. Iron(II) refers to iron with a 2+ charge, and bromide is the anion form of bromine. When soluble ionic compounds like iron(II) bromide dissolve in water, they dissociate into their constituent ions, contributing to the compound's solubility.
Step-by-step Explanation:
- Recognize that iron(II) indicates a bivalent iron, meaning it has lost two electrons to form the Fe2+ cation.
- Recognize that bromide refers to the Br− anion.
- Combine the cation and anion in a 1:2 ratio to achieve electrical neutrality, which gives us the formula FeBr2.
- Upon dissolving in water, FeBr2 will dissociate into Fe2+ and two Br− ions.