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Find the surface area of revolution about the x-axis of y=3sin(5x) over the interval 0≤x≤π/5?

User Crocboy
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Final answer:

To find the surface area of revolution about the x-axis of y=3sin(5x) over the interval 0≤x≤π/5, we can use the formula for surface area of revolution and evaluate the integral.

Step-by-step explanation:

To find the surface area of revolution about the x-axis of y=3sin(5x) over the interval 0≤x≤π/5, we can use the formula for surface area of revolution:

SA = ∫2πy√(1+(dy/dx)²)dx

First, we find the derivative of y with respect to x: dy/dx = 3cos(5x).

Then, we substitute the given values into the formula and integrate from 0 to π/5:

SA = ∫[0,π/5] 2π(3sin(5x))√(1+(3cos(5x))²)dx

After evaluating the integral, we can find the surface area of revolution about the x-axis.

User Tim Harrison
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