Final answer:
To depict the line bond structure of CH3CH2CH2CH2COCl, start with the carbon chain, add chlorine to the terminal carbon, and include a double bond between the last carbon and an oxygen atom, resulting in a tetrahedral geometry around the carbons and a planar geometry at the carbonyl carbon.
Step-by-step explanation:
The question involves drawing the line bond structure of the organic compound CH3CH2CH2CH2COCl, also known as butyryl chloride. Start by drawing the parent chain of five carbon atoms, which forms the backbone of the molecule:
H3C-CH2-CH2-CH2-C-Cl
Then, add the chlorine atom to the carbon atom at the end of the chain. Because the molecule includes a carbonyl group (C=O), we need to indicate a double bond between the carbon atom and the oxygen next to the chlorine atom. The final structure now reflects the molecule with all bonds and atoms:
H3C-CH2-CH2-CH2-C(=O)-Cl
Each carbon atom has a tetrahedral molecular geometry except for the carbon in the carbonyl group, which is planar due to the double bond to oxygen.