The equation of the line passing through the point (1, -2) with a slope of -3 is y = -3x + 1.
To find the equation of a line that passes through the point (1, -2) with a slope of -3, we can use the point-slope form of a linear equation: y - y1 = m(x - x1). In this case, x1 = 1, y1 = -2, and m = -3.
Substituting these values into the equation, we get y - (-2) = -3(x - 1), which simplifies to y + 2 = -3x + 3.
Finally, by rearranging the equation to the slope-intercept form (y = mx + b), we get y = -3x + 1.
The probable question may be: "Find the equation of the line that passes through the point (1,-2) with a slope of -3".